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During the first overtime period medications like abilify proven 500mg baycip, Denver had the opportunity to kick a field goal medicine park ok quality baycip 500mg, with the ball placed at a distance of 29 m from the goalposts medicine ball slams generic baycip 500 mg. If the ball was kicked with the horizontal component of initial velocity being 18 m/s and a flight time of 2 s treatment 4 addiction effective baycip 500mg, was the kick long enough to make the field goal? If the goal is to determine the maximum height achieved by a projectile, v2 in equation 3 may be set equal to zero: 2 0 5 v1 2ad (3A) An example of this use of equation 3A is shown in Sample Problem 10. If the problem is to determine the total flight time, one approach is to calculate the time it takes to reach the apex, which is one-half of the total flight time if the projection and landing heights are equal. In this case, v2 in equation 1 for the vertical component of the motion may be set equal to zero because vertical velocity is zero at the apex: 0 5 v1 at (1A) Sample Problem 10. When using the equations of constant acceleration, it is important to remember that they may be applied to the horizontal component of projectile motion or to the vertical component of projectile motion, but not to the resultant motion of the projectile. If the horizontal component of motion is being analyzed, a 5 0, but if the vertical component is being analyzed, a 5 9. The equations of constant acceleration and their special variations are summarized in Table 10-4. Equation 2 contains d but also contains the variable t, which is an unknown quantity in this problem. Equation 3 contains the variable d, and, recalling that vertical velocity is zero at the apex of the trajectory, Equation 3A can be used to find d: 2 2 v2 5 v1 2ad 2 0 5 v1 2ad 0 5 (15 m/s)2 (19. Solution vh 5 12 cos 35 m/s vv 5 12 sin 35 m/s Vv 12 m/s 358 12 m/s 358 Vh How high does the ball go? Equation 2H for horizontal motion cannot be used because t for which the ball was in the air is not known. Equation 1A can be used to solve for the time it took the ball to reach its apex: 0 5 v1 at 0 5 12 sin 35 m/s t5 6. Linear kinematic quantities include the scalar quantities of distance and speed, and the vector quantities of displacement, velocity, and acceleration. Depending on the motion being analyzed, either a vector quantity or its scalar equivalent and either an instantaneous or an average quantity may be of interest. A projectile is a body in free fall that is affected only by gravity and air resistance. The two components are independent of each other, and only the vertical component is influenced by gravitational force. Factors that determine the height and distance the projectile achieves are projection angle, projection speed, and relative projection height. The equations of constant acceleration can be used to quantitatively analyze projectile motion, with vertical acceleration being 29. A runner completes 61/2 laps around a 400 m track during a 12 min (720 s) run test. A wheelchair marathoner has a speed of 5 m/s after rolling down a small hill in 1. An orienteer runs 400 m directly east and then 500 m to the northeast (at a 45° angle from due east and from due north). Provide a graphic solution to show final displacement with respect to the starting position. Why are the horizontal and vertical components of projectile motion analyzed separately? A soccer ball is kicked with an initial horizontal speed of 5 m/s and an initial vertical speed of 3 m/s. Assuming that projection and landing heights are the same and neglecting air resistance, identify the following quantities: a. A tennis ball leaves a racket during the execution of a perfectly horizontal ground stroke with a speed of 22 m/s. Answer the following questions pertaining to the split times (in seconds) presented below for Ben Johnson and Carl Lewis during the 100 m sprint in the 1988 Olympic Games. If the current is flowing at 2 m/s to the northeast, where will the boat be in 10 min with respect to its starting position?   